SOLUTION: Larry, Curly and Mo assembled a puzzle together in 40 hours. If Curly worked twice as fast as Mo and Larry worked just as fast as Curly, then how long would it have taken Mo to as

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Larry, Curly and Mo assembled a puzzle together in 40 hours. If Curly worked twice as fast as Mo and Larry worked just as fast as Curly, then how long would it have taken Mo to as      Log On


   



Question 666907: Larry, Curly and Mo assembled a puzzle together in 40 hours. If Curly worked twice as fast as Mo and Larry worked just as fast as Curly, then how long would it have taken Mo to assemble the puzzle alone?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Add their rates of working to get their rate of working together
Let Mo's rate is ( 1 puzzle done ) / ( t hours )
Curly's rate is ( 2 puzzles done ) / ( t hours )
Larry's rate is ( 2 puzzles done ) / ( t hours }
---------------
+1%2Ft+%2B+2%2Ft+%2B+2%2Ft+=+1%2F40+
Multiply both sides by +40t+
+40+%2B+80+%2B+80+=+t+
+t+=+200+
+2t+=+400+
Mo took 200 hrs to assemble the puzzle
check:
+1%2F200+%2B+2%2F200+%2B+2%2F200+=+1%2F40+
+5%2F200+=+1%2F40+
+1%2F40+=+1%2F40+
OK