SOLUTION: Mary and Jane could finish a job in 1 hour. After Mary worked in the job for 2 hours, Jane joined her and together they finished the job in 20 minutes. How long will each of them f

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Mary and Jane could finish a job in 1 hour. After Mary worked in the job for 2 hours, Jane joined her and together they finished the job in 20 minutes. How long will each of them f      Log On


   



Question 582314: Mary and Jane could finish a job in 1 hour. After Mary worked in the job for 2 hours, Jane joined her and together they finished the job in 20 minutes. How long will each of them finish the job working alone?
*please answer the problem with 2 equations and 2 unknowns(x and y). thanks!

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Mary and Jane could finish a job in 1 hour. After Mary worked in the job for 2 hours, Jane joined her and together they finished the job in 20 minutes. How long will each of them finish the job working alone?
*please answer the problem with 2 equations and 2 unknowns(x and y). thanks!
Let x = the number of hours it would take Mary to finish 1 job working alone.
Let y = the number of hours it would take Jane to finish 1 job working alone.

20 minutes = 1/3 hour

Make this chart:
                          No. of jobs     No. of      Rate 
                          or fraction     hours        in
                          thereof         worker    jobs/hour
M. alone for x hours           1            x
J. alone for y hours           1            y
M. and J. together for 1 hr    1            1          1
M. alone for 2 hours                        2
M. and J. together for 1/3 hr              1/3

Fill in the rates in jobs/hour in the first two cases by dividing
jobs done by the number of hours:

                          No. of jobs     No. of      Rate 
                          or fraction     hours        in
                          thereof         worker    jobs/hour
M. alone for x hours           1            x         1/x
J. alone for y hours           1            y         1/y
M. and J. together for 1 hr    1            1          1
M. alone for 2 hours                        2
M. and J. together for 1/3 hr              1/3

We can now fill in M's rate working alone for 2 hours as the same
rate 1/x.  We can also fill in the rate of them working together for
1/3 hour as the same 1 job/hour rate as when they work for 1 hour.


                          No. of jobs     No. of      Rate 
                          or fraction     hours        in
                          thereof         worker    jobs/hour
M. alone for x hours           1            x         1/x
J. alone for y hours           1            y         1/y
M. and J. together for 1 hr    1            1          1
M. alone for 2 hours                        2         1/x
M. and J. together for 1/3 hr              1/3         1
  
Now we can fill in the no. of jobs or fraction thereof (actually fraction
tereof) that M. did alone for 2 hours by multiplying her rate times her
time (2 hours) getting 2/x.  Similar we can fill in the fraction of a 
job that they did together in 1/3 hour by multiplying their combined 
rate 1 job/hour by 1/3 hour.

                             No. of jobs     No. of      Rate 
                             or fraction     hours        in
                             thereof         worker    jobs/hour
M. alone for x hours              1            x         1/x
J. alone for y hours              1            y         1/y
M. and J. together for 1 hr       1            1          1
M. alone for 2 hours             2/x           2         1/x
M. and J. together for 1/3 hr    1/3          1/3         1

Our two equations come from:

             %28matrix%284%2C1%2C%0D%0A%0D%0A%22Mary%27s%22%2Crate%2Cworking%2Calone%29%29 + %28matrix%284%2C1%2C%0D%0A%0D%0A%22Jane%27s%22%2Crate%2Cworking%2Calone%29%29 = %28matrix%285%2C1%2C%0D%0A%0D%0ATheir%2Ccombined%2Crate%2Cworking%2Ctogether%29%29 

              +  = %28matrix%283%2C1%2C%0D%0A%0D%0A1%2Ccomplete%2C+job%29%29 

or

            1%2Fx + 1%2Fy = 1 
            2%2Fx + 1%2F3 = 1

Solve that system and get x = 3 and y = 3%2F2 or 1.5 hours

So Mary takes 3 hourse to do the job and Jane takes 1.5 hours

Edwin