You can put this solution on YOUR website! the sum of the reciprocals of two consecutive even integers is 13/84 .find these integers
**
let x=first integer
x+2=consecutive even integer
..
(1/x)+(1/(x+2))=13/84
LCD:84x(x+2)
84(x+2)+84x=13x(x+2)
84x+168+84x=13x^2+26x
13x^2-142x-168=0
solve by following quadratic formula:
a=13, b=-142, c=-168
Ans:
x≈-1.077 (reject, not an integer)
or
x=12
x+2=14
ans:
integers are: 12 & 14