SOLUTION: Any help would surely be appreciated. "If Cody and Hunter painted the room together, it would take them 4 hours and 57 minutes. Cody would be able to paint a room 3 hours and 3 m
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: Any help would surely be appreciated. "If Cody and Hunter painted the room together, it would take them 4 hours and 57 minutes. Cody would be able to paint a room 3 hours and 3 m
Log On
Question 448312: Any help would surely be appreciated. "If Cody and Hunter painted the room together, it would take them 4 hours and 57 minutes. Cody would be able to paint a room 3 hours and 3 minutes faster if Hunter helped. Figure out how long each person needs to paint a room alone". Thanks. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! "If Cody and Hunter painted the room together, it would take them 4 hours and 57 minutes.
Cody would be able to paint a room 3 hours and 3 minutes faster if Hunter helped.
Figure out how long each person needs to paint a room alone".
:
Let's do this in minutes.
4 hrs 57 min = 297 min
3 hrs 3 min = 183 min
:
Let c = Cody's time alone
Let h = Hunter's time alone
:
Let the completed job = 1 (a painted room)
: + = 1
:
"Cody would be able to paint a room 3 hours and 3 minutes faster if Hunter helped."
So we can say:
c - 183 = 297
c = 297 + 183
c = 480 min Cody alone (8 hrs)
:
Replace c with 480, find h: + = 1
Multiply by 480h, results
297h + 480(297) = 480h
142560 = 480h - 297h
183h = 142560
h =
h = 779 min Hunter alone (12 hrs, 59 minutes)
:
:
See if that checks out + = 1
.61875 + .38126 ~ 1, so we can say
:
Cody, 8 hrs alone
Hunter, 12 hr 59 min alone
