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Question 23843: Next door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know it takes 18 hours using both houses. They also know that Bob's hose, used alone, takes 20% less time than Jim's hose alone. How much time is required to fill the pool by each hose alone?
Thanks for your help!
Dan
Found 4 solutions by elima, adamhen894, josgarithmetic, ikleyn: Answer by elima(1433) (Show Source):
You can put this solution on YOUR website! First of all let;
x=Jim's hose
x-.20x=Bob's hose
x+(x-.20x)=18
2x-.20x=18
1.8x=18
x=10
So now we have what Jim's hose would do, and we know Bob's hose takes 20% less time, so;
10-.20=2
So bob's hose;
10-2=8
Now the two together;
10+8=18
=)
Answer by adamhen894(15) (Show Source):
You can put this solution on YOUR website! let x be amount of time(in hours) Jim uses hose to fill the pool alone.
Bob takes 20% less time than Jim's to fill the pool alone. x-0.2x= 0.8x
it takes 18 hours for Bob and Jim to fill the pool together.
in one hour,
Jim can dnoe 1/x of job
Bob can 1/0.8x of job (also equals 5/4x)
together they can done 1/18 of job
1/x + 5/4x = 1/18
(4+5)/4x = 1/18
x=40.5 ( # of hours for Jim to fill the pool alone)
& for Bob, it takes 32.4 hour to fill the pool alone.
if you have any other ways of solving it, email me, i would love to hear that!!! adamchen894@gmail.com
Answer by josgarithmetic(39614) (Show Source): Answer by ikleyn(52759) (Show Source):
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