SOLUTION: Can you please help me with this problem? A hose can fill a swimming pool in 6 hrs. Another hose needs 3 more hrs to fill the pool than the two hoses combined. How long would it ta

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Can you please help me with this problem? A hose can fill a swimming pool in 6 hrs. Another hose needs 3 more hrs to fill the pool than the two hoses combined. How long would it ta      Log On


   



Question 211569This question is from textbook
: Can you please help me with this problem? A hose can fill a swimming pool in 6 hrs. Another hose needs 3 more hrs to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool? Please show me the steps and please get back to me before Tues. 10am.
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This question is from textbook

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A hose can fill a swimming pool in 6 hours. Another hose needs 3 more hours to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool.
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h1 takes 6 hours, so it fills 1/6 pool per hour.
h2 takes x hours, so it fills 1/x pool per hour.
Together, they do 1/6 + 1/x per hour.
1/6 + 1/x = (x+6)/6x per hour (together), so it takes 6x/(x+6) hours.
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The time the 2nd hose takes, x hours, is 3 hours more than the time together.
x-3 = 6x/(x+6)
(x-3)*(x+6) = 6x

(x-6)*(x+3) = 0
x = 6 hours (Ignore the -3 hours)
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Each hose takes 6 hours. Together they take 3 hours, so the time for the 2nd hose is 3 hours more than the 3 hours together.