SOLUTION: the intensity at which an object is illuminated varies inversely as the square of its distance from the light source. At 1.5 ft from a light bulb, the intensity of the light is 60
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Question 1183767: the intensity at which an object is illuminated varies inversely as the square of its distance from the light source. At 1.5 ft from a light bulb, the intensity of the light is 60 units. What is the intensity at 1 ft?
You can put this solution on YOUR website! the formula to use is y = k/x^2.
y is the intensity.
x is the distance from the light source.
k is the constant of variation.
when x = 1.5, y = 60
the formula becomes 60 = k / 1.5^2
solve for k to get:
k = 60 * 1.5^2 = 135.
when x = 1, the formula becomes:
y = 135 / 1 = 135.
that's the intensity of the light when the light source is 1 feet away.
