SOLUTION: A boat can travel 39mph in still water. If it travels 235 miles with the current in the same length of time it travels 155 miles against the current, what is the speed of the curre

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A boat can travel 39mph in still water. If it travels 235 miles with the current in the same length of time it travels 155 miles against the current, what is the speed of the curre      Log On


   



Question 1158073: A boat can travel 39mph in still water. If it travels 235 miles with the current in the same length of time it travels 155 miles against the current, what is the speed of the current?

Found 4 solutions by josgarithmetic, ikleyn, MathTherapy, jim_thompson5910:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
c, the speed of current

highlight_green%28235%2F%2839%2Bc%29=155%2F%2839-c%29%29
Solve for c.

Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.

The time equation is


    235%2F%2839%2Bx%29 = 155%2F%2839-c%29.


Cancel factor 5 in both sides


    47%2F%2839%2Bx%29 = 31%2F%2839-c%29.


Obviously,  x = 8 is the solution.


ANSWER.  8 miles per hour.

Solved.

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For your info:

    such a speed usually is considered as too high for a river to travel on it by boat.

The following useful info is from this web-site

https://hypertextbook.com/facts/2006/NervanaGaballa.shtml

    The speed of a river varies from close to 0 m/s to 3.1 m/s (7 mph). Factors that affect the speed of a river 
    include the slope gradient, the roughness of the channel, and tides. Rivers tend to flow from a higher elevation 
    to a lower elevation. The gradient is the drop of the elevation of a river. 

    Therefore, the rivers speed is at its maximum at the headwaters (high gradient, high energy) 
    and at its minimum at the base level (no gradient, lowest energy). 
    An incoming tide can reverse a river and cause it to flow against the gradient -- uphill!


Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!
A boat can travel 39mph in still water. If it travels 235 miles with the current in the same length of time it travels 155 miles against the current, what is the speed of the current?
Let speed of current be C
Then we get the following TIME equation: matrix%281%2C3%2C+235%2F%2839+%2B+C%29%2C+%22=%22%2C+155%2F%2839+-+C%29%29
matrix%281%2C3%2C+47%2F%2839+%2B+C%29%2C+%22=%22%2C+31%2F%2839+-+C%29%29 ---- Factoring out, GCF, 5, in numerator
31(39 + C) = 47(39 - C) ------ Cross-multiplying
31(39) + 31C = 47(39) - 47C
31C + 47C = 47(39) - 31(39)
78C = 16(39)
Speed of current, or

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

There are already great answers here. I'll just provide a way to set up the equation mentioned.

C = speed of current
39+C = the speed of the boat when it is going downstream (it is sped up 39 mph)
39-C = speed of boat when it is going upstream (it is slowed down by 39 mph)
Basically the boat naturally goes 39 mph, but the current will help or hinder the boat to speed up or slow down. Which is why we add or subtract that C value.

Now we use the idea that
distance = rate*time
d = r*t

Solve for t to get
t = d/r

If the boat travels 235 miles with the current (downstream), then it goes a speed of 39+C mph, and the time it takes to do so is...
t = d/r
t = 235/(39+C)

Furthermore, if the boat goes 155 miles against the current (upstream), then it goes a speed of 39-C mph, and the time it takes to do so is...
t = d/r
t = 155/(39-C)

Both time values (t) are the same in this case due to the instructions stating so. Therefore, we are able to equate the right hand sides of the equations t = 235/(39+C) and t = 155/(39-C) to get 235/(39+C) = 155/(39-C)

From here you would solve for C as directed in the steps provided by @MathTherapy