SOLUTION: a ball is thrown from a height of 45 meters with an initial downward velocity of 10 m/s. The balls height h (in meters) after t seconds is given by the following.
H=45-10t-5t^2
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-> SOLUTION: a ball is thrown from a height of 45 meters with an initial downward velocity of 10 m/s. The balls height h (in meters) after t seconds is given by the following.
H=45-10t-5t^2
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Question 1150374: a ball is thrown from a height of 45 meters with an initial downward velocity of 10 m/s. The balls height h (in meters) after t seconds is given by the following.
H=45-10t-5t^2
How long after the ball is thrown does it hit the ground?
Round to nearest hundredth
*will someone help me with the answer Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a ball is thrown from a height of 45 meters with an initial downward velocity of 10 m/s. The balls height h (in meters) after t seconds is given by the following.
H=45-10t-5t^2
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At impact, 45-10t-5t^2 = 0
Solve for t.
