SOLUTION: mogaka and onduso working together can do a piece of work in 6 days. mongaka, working alone takes 5 days longer than onduso. how many days does it take onduso to do the work alone?
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Question 1149843: mogaka and onduso working together can do a piece of work in 6 days. mongaka, working alone takes 5 days longer than onduso. how many days does it take onduso to do the work alone? Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52747) (Show Source):
The setup is this equation
+ = ,
where x is the number of days under the question.
Simplify and solve step by step. The first step is to multiply equation (1) by 6x(x+5).
6(x+5) + 6x = x*(x+5)
6x + 30 + 6x = x^2 + 5x
x^2 - 7x - 30 = 0.
(x-10)*(x+3) = 0.
There are two roots, x= 10 and x= -3; only positive root makes sense.
So, only the root x= 10 satisfies the problem's conditions.
Answer. It will take Onduso 10 days to do the work alone.
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mogaka and onduso working together can do a piece of work in 6 days. mongaka, working alone takes 5 days longer than onduso. how many days does it take onduso to do the work alone?
Let the time that Onduso takes to do the job alone, be x
Then time Mogaka takes to do the job, alone = x + 5
Then Onduso and Magaka can do and of the job, respectively, in 1 day
We then get:
Solve for x, the time it takes Onduso to do the job alone.
You should get
