SOLUTION: Jim goes out on a walk just before 2 p.m. every day, when the hands of the clock make a 90 degree angle. He arrives back home after 3 p.m. when the hands of the clock first make a

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Jim goes out on a walk just before 2 p.m. every day, when the hands of the clock make a 90 degree angle. He arrives back home after 3 p.m. when the hands of the clock first make a       Log On


   



Question 1147940: Jim goes out on a walk just before 2 p.m. every day, when the hands of the clock make a 90 degree angle. He arrives back home after 3 p.m. when the hands of the clock first make a 20 degree angle. How many hours does he spend walking in June.
Answer by greenestamps(13195) About Me  (Show Source):
You can put this solution on YOUR website!


The minute hand starts 90 degrees "behind" the hour hand and finishes 20 degrees "ahead of" the hour hand. So in the time the hour hand moves x degrees, the minute hand moves x+110 degrees.

But the minute hand moves 12 times as fast as the hour hand (12 revolutions in 12 hours for the minute hand; 1 for the hour hand.) So

x%2B110+=+12%28x%29
110+=+11x
x+=+10

The hour hand moves 10 degrees on each of his walks. Since the hour hand moves 30 degrees in 1 hour (360 degrees in 12 hours), each of his walks is 20 minutes, or 1/3 hour.

There are 30 days in June, so the number of hours he spends walking in June is 30*(1/3) = 10.

ANSWER: 10 hours of walking in June.