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Question 1134010: A vessel can be build by Pipe A in 4 hours and Pipe B in 8 hours. Each working independently. At 8 AM, Pipe A has started. At what time will the vessel refill the Pipe B in an hour later?
Found 2 solutions by Boreal, ankor@dixie-net.com:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! in 1 hour, it is 1/4 full by Pipe A and in 1 hour 1/8 full by Pipe B.
in x hours, it is x/4 full by Pipe A and x/8 full by Pipe B.
in x hours, it is x/4 full by Pipe A and (x-1)/8 full by Pipe B and that sum equals 1, completely full.
multiply everything by 8, LCD.
2x+x-1=8
3x=9
x=3 hours
In 3 hours, it is 3/4 full by Pipe A and 2/8 or 1/4 full by Pipe B. It is full.
11 am.
Answer by ankor@dixie-net.com(22740)  (Show Source):
You can put this solution on YOUR website! Edited to make more sense
A vessel can be filled by Pipe A in 4 hours and Pipe B in 8 hours.
Each working independently.
At 8 AM, Pipe A has started.
At what time will the vessel be filled if Pipe B starts an hour later?
:
Let t = the filling time by pipe A
then
(t-1) = the filling time by pipe B
let the full vessel = 1
:
 +  = 1
multiply equation by 8, cancel denominators
2t + (t-1) = 8
2t + t = 8 + 1
3t = 9
t = 9/3
t = 3 hrs from 8:00 which is at 11:00 when the vessel will filled
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