SOLUTION: A man waters, with a garden hose, a contained area of 2.26 feet. If the volume of water coming out of the hose fills a 10 quart pail in 2 minutes, what is the "rainfall" depth (in
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: A man waters, with a garden hose, a contained area of 2.26 feet. If the volume of water coming out of the hose fills a 10 quart pail in 2 minutes, what is the "rainfall" depth (in
Log On
Question 1133171: A man waters, with a garden hose, a contained area of 2.26 feet. If the volume of water coming out of the hose fills a 10 quart pail in 2 minutes, what is the "rainfall" depth (in inches) equivalent if he runs the hose for 12 minutes?
Show all work. Some conversion factors you may need:
1 gallon = 8 pounds
1 cubic foot = 62.4 pounds
(pi) r^2 h = volume of a cylinder
d = 2r Answer by greenestamps(13198) (Show Source):
I will assume the contained area is 2.26 SQUARE feet....
Use the given flow rate and the given amount of time to determine the number of cubic feet of water; the depth (in feet) is that volume of water, divided by the area. Then convert the answer in feet to inches.
The conversion can be accomplished using several unit multipliers.
Volume of water in 12 minutes:
10 qt 1 gal 8 pounds 1 cu ft
12 min * ------- * ------- * ---------- * -------------
2 min 4 qt 1 gal 62.4 pounds
Then divide by the area to get the depth in feet; then multiply by 12 to get the depth in inches.
