SOLUTION: A container filled with 30 litres of wine had 5 litres of wine removed. To fill the container. 5 litres of water was added. The next day 12 litres of the mixture was removed, and r
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Question 1105123: A container filled with 30 litres of wine had 5 litres of wine removed. To fill the container. 5 litres of water was added. The next day 12 litres of the mixture was removed, and replaced with an equal amount of water. What fraction of the final mixture was water?
Found 2 solutions by josmiceli, JThomson:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
This problem makes the assumption that after
a liquid is added to a different liquid, they
become thoroughly mixed.
-----------------------------------------
liters of wine
and liters water
-----------------------------
liters of the mixture is removed
liters is wine
liters is water
Then liters of water is added
-------------------------------------
Now there is:
liters of wine
liters of water
7/12 of the final mixture is water
check the math
Answer by JThomson(12) (Show Source): You can put this solution on YOUR website!
After 5 litres of wine is removed and 5 litres of water added, the ratio of
wine to water is 25 : 5;
Thus there is 5/6 wine and 1/6 water in the mixture now;
When 12 litres of the mixture is removed;
(5/6)×12 = 10 litres of wine is removed;
Also (1/6)×12 = 2 litres of water is removed.
Ratio of wine to water remaining is (25-10):(5-2)= 15:3;
After 12 litres of water has been added to mixture, ratio of wine to water
becomes, 15:(3+12) = 15:15 = 1:1
Fraction of water in the mixture now is 1/2.
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