SOLUTION: A farmer bought 100 ha of land, part at $1850 per hectare and part at $2250 paying for the whole $217000. How much land was there in each part? Do not round intermediate

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A farmer bought 100 ha of land, part at $1850 per hectare and part at $2250 paying for the whole $217000. How much land was there in each part? Do not round intermediate       Log On


   

Question 1097779: A farmer bought 100 ha of land, part at $1850 per hectare and part at $2250


paying for the whole $217000. How much land was there in each part?
Do not round intermediate results. Round only final answers. Round to the whole.

ha at $1850/ha
ha at $2250/ha
Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
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Let  "x" be the the area bought at $1850, measured in "ha".


Then the remaining area is (100-x) ha.


The "money equation" is


1850*x + 2250*(100-x) = 217000.


Simplify and solve for x.


1850x + 225000 - 2250x = 217000,

-400x = 217000 - 225000 = -8000  ====>  x = %28-8000%29%2F%28-400%29 = 80%2F4 = 20.


Answer.  20 ha was bought at $1850.  100-20 = 80 ha was bought at $2250.


Check.   20*1850 + 80*2250 = 217000.   ! Correct !

Solved.