SOLUTION: A certain concrete mixture contains 5.00% cement and 7.00% sand ,How many kilograms of this mixture and how many kilograms of sand should be combined with 255 kg of cement to make
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Question 1097639: A certain concrete mixture contains 5.00% cement and 7.00% sand ,How many kilograms of this mixture and how many kilograms of sand should be combined with 255 kg of cement to make a batch that is 16.0% cement and 18.0% sand? Carry out all calculations exactly and round to three significant digits final answers only.
Let "x" be the amount/the mass of the original mixture which should be combined (in kilograms).
Let "y" be the amount/the mass of the (outside) sand which should be combined (in kilograms)
Then you have the system of these two equations for x and y:
= 0.16 (1) (to provide the cement 16% content)
= 0.18 (2) (to provide the sand 18% contents)
Simplify by multiplying both sides of each equation by the respective denominator. You will get
0.05x + 255 = 0.16*(x + y + 255), (3)
0.07x + y = 0.18*(x + y + 255). (4)
Simplify the system one step further by multiplying both sides of the equations by 100. You will get
5x + 25500 = 16*(x + y + 255), (5)
7x + 100y = 18*(x + y + 255). (6)
Write the system in canonical/standard form
11x + 16y = 21420, (7)
11x - 82y = -4590. (8)
The setup is completed. The rest is arithmetic and the technique for solving this system.
First step in solving is to subtract equation (8) from the equation (7). You will get
98y = 21420 + 4590 = 26010 ====> y = = 265.408 kg of of the (outside) sand.
Having the found value of y, you can calculate x from the equation (7)
x = = = 1561.225 kg.
Answer. 1561.225 kg of the original mixture and 265.408 kg of the (outside) sand should be added.
Check. Eq(1): = 0.16.
Eq(2): = 0.18.