SOLUTION: Sally left point A at 6 am and reached point B at 10 am. Jane left one hour later and arrived at point B at the same time as sally. Jane traveled two miles an hour faster than sall

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Sally left point A at 6 am and reached point B at 10 am. Jane left one hour later and arrived at point B at the same time as sally. Jane traveled two miles an hour faster than sall      Log On


   



Question 1069776: Sally left point A at 6 am and reached point B at 10 am. Jane left one hour later and arrived at point B at the same time as sally. Jane traveled two miles an hour faster than sally.
How far did sally and jane travel?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate * Time = Distance,
For Sally,
R%5BS%5D%2A4=D
For Jane,
R%5BJ%5D%2A3=D
and
R%5BJ%5D=R%5BS%5D%2B2
So,
R%5BS%5D%2A4=R%5BJ%5D%2A3
Substituting,
R%5BS%5D%2A4=%28R%5BS%5D%2B2%29%2A3
4%2AR%5BS%5D=3%2AR%5BS%5D%2B6
R%5BS%5D=6mph
So,
D=6%2A4
D=24miles