SOLUTION: sagar& Akash ran 2km race twice.Akash completed first round two minutes earlier than sagar.Then in second round sagar increased speed by 2km/hr then sagar finished the round 2 mi

Let  a = Acash speed in the first round (in km/min),
     s = Sagar speed in the first round.

We have 

 = 2        minutes   (first round)     (1)

 = 2     minutes   (second round)    (2)


Add the two equations (1) and (2)  (both sides).  You will get

 = 4.

Solve this equation for "s". For it, multiply both sides by s*(s+2). You will get

2*(s+2) - 2s = 4s*(s+2).

2s + 4 -2s = 4s^2 + 8s,

4s^2 + 8s - 4 = 0,

s^2 + 2s - 1 = 0,

 =  = .

Only positive root works:  s =  km/min.  

It is the speed of Sagar in the first round.

Then the speed of Acash was a =  km/min in the first round.