SOLUTION: If Janet can paint a wall in 10 hours but working with Linda, both of them can paint the fence in 4 hours. How long would it have taken Janet to paint the fence alone?

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Question 1064332: If Janet can paint a wall in 10 hours but working with Linda, both of them can paint the fence in 4 hours. How long would it have taken Janet to paint the fence alone?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The time for Linda to paint the wall working alone is y:
%28%281%2F10%29%2B%281%2Fy%29%29%2A4=1

SOLVE FOR y.


Your normal fractions skills.
LCD or simplest denominator is 10y.

4%2F10%2B4%2Fy=1

Multiply left and right by 10y.

4y%2B40=10y

40=6y
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