SOLUTION: I drove to my parents' house at 60 miles per hour. If I had driven 50 miles an hour instead, then I would have gotten there 40 minutes later. How many miles did I drive?

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Question 1060240: I drove to my parents' house at 60 miles per hour. If I had driven 50 miles an hour instead, then I would have gotten there 40 minutes later. How many miles did I drive?
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
RT=D Constant Travel Rate Rule

                 SPEED       TIME       DISTANCE

DONE              60          t            d

HYPTHETICAL       50         t+2/3         d


Same distance but different speeds and times.
60t=50%28t%2B2%2F3%29
Solve this for t.

Now evaluate d=60t.

Answer by ikleyn(52767) About Me  (Show Source):
You can put this solution on YOUR website!
.
I drove to my parents' house at 60 miles per hour. If I had driven 50 miles an hour instead,
then I would have gotten there 40 minutes later. How many miles did I drive?
~~~~~~~~~~~~~

Let D be the distance under the question.

When you drove to parents at 60 mph, you spent D%2F60 hours.

When you drove back at 50 mph, you spent D%2F50 hours.

The difference was 40 minutes, or 2%2F3 of an hour.

It gives you an equation

D%2F50+-+D%2F60 = 2%2F3.

To solve it, multiply both sides by 300. You will get

6D - 5D = 200,  or

D = 200.

Answer.  The distance was 200 miles.

Check.   200%2F50 = 4 hours.  200%2F60 = 3 1%2F3 hours.  4 hours - 3 1%2F3 hour = 2%2F3 hour.  Correct !

Solved.


Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

I drove to my parents' house at 60 miles per hour. If I had driven 50 miles an hour instead, then I would have gotten there 40 minutes later. How many miles did I drive?
Let the distance be D
Then actual time taken = D%2F60
Hypothetical time: D%2F50
Note that 40 minutes = matrix%281%2C4%2C+40%2F60%2C+or%2C+2%2F3%2C+hour%29
We then get the following TIME equation: D%2F60+=+D%2F50+-+2%2F3
Solve for D, the distance
That's all...nothing complex!
Also, NO NEED TO find actual and/or hypothetical time. That's doing more work than is required, unless of course you like doing extra work.