SOLUTION: Rowing with the current, a canoeist paddled 18 mi in 3 h. Against the current, the canoeist could paddle only 6 mi in the same amount of time.
Find the rate of the canoest in c
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-> SOLUTION: Rowing with the current, a canoeist paddled 18 mi in 3 h. Against the current, the canoeist could paddle only 6 mi in the same amount of time.
Find the rate of the canoest in c
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Question 1054176: Rowing with the current, a canoeist paddled 18 mi in 3 h. Against the current, the canoeist could paddle only 6 mi in the same amount of time.
Find the rate of the canoest in calm water and the rate of the current. Answer by ikleyn(52778) (Show Source):
You can put this solution on YOUR website! .
Rowing with the current, a canoeist paddled 18 mi in 3 h. Against the current, the canoeist could paddle only 6 mi in the same amount of time.
Find the rate of the canoeist in calm water and the rate of the current.
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Your equations are
(1) = u + v, ("Rowing with the current, a canoeist paddled 18 mi in 3 h")
(2) = u - v. ("Against the current, the canoeist could paddle only 6 mi in the same amount of time.")
Here u is the rate of the canoeist in calm water and v is the rate of the current.
Simplify equations (1) and (2). You will get
u + v = 6, (3)
u - v = 3. (4)
Add equations (3) and (4). You will get
2u = 6 + 3 = 9 ---> u = = 4.5.
Thus you just found the rate of the canoeist in calm water. It is 4.5 mph.
Now find v from (3):
v = 6 - u = 6 - 4.5 = 1.5 mph.
Answer. The rate of the canoeist in calm water is 4.5 mph.
The rate of the current is 1.5 mph.
