SOLUTION: Paul can do a certain job in half the time that Jim requires to do it. Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. What length of time, in ho

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Paul can do a certain job in half the time that Jim requires to do it. Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. What length of time, in ho      Log On


   



Question 1038207: Paul can do a certain job in half the time that Jim requires to do it. Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. What length of time, in hours, would Paul, working alone, take to do the whole job?
Found 6 solutions by mananth, MathTherapy, ikleyn, n2, josgarithmetic, KMST:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
Paul can do a certain job in half the time that Jim requires to do it.

Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. What length of time, in hours, would Paul, working alone, take to do the whole job?
Let jim take x hours to do the job
So he does 1/x of the job in 1 hour
Paul takes x/2 hours to do the job
so he does 2/x of the job in 1 hour
After jim worked for 1 hour balance job was
(1-1/x) = (x-1)/x
Paul does 2/x of the job in 1 hour
so he takes ((x-1)/x)/(2/x) hours to do the remaing job
((x-1)/x)/(2/x) = 10
(x-1)/x =5x
x-1=5
x= 4 No of hours Jim takes to complete the job
Paul will take 2 hours




Answer by MathTherapy(10719) About Me  (Show Source):
You can put this solution on YOUR website!

Paul can do a certain job in half the time that Jim requires to do it. Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. What length of time, in hours, would Paul, working alone, take to do the whole job?
Working alone, Paul takes: highlight_green%28matrix%281%2C2%2C+10%261%2F2%2C+hours%29%29 to do the job 


Answer by ikleyn(53619) About Me  (Show Source):
You can put this solution on YOUR website!
.
Paul can do a certain job in half the time that Jim requires to do it.
Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours.
What length of time, in hours, would Paul, working alone, take to do the whole job?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


        The solution by @mananth to this problem is INCORRECT.
        It is obvious if to compare his answer with the given data in the problem.

        I came to bring a correct solution.


Let 'a' be the Jim's rate of work, i.e. part of work, which Jim makes in 1 hour.

Then the Paul's rate of work is 2a, according to the problem.


Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. 


It means that

    a + 10*(2a) = 1,    where '1' represents the whole job.


From this equation, we find

    a + 20a = 1  --->  21a = 1  --->  a = 1/21.


It means that Jim makes 1/21 of the Job per hour.
In other words, Jim needs 21 hours to make the whole job alone.

Hence, according to the problem, Paul needs half of 21 hours to make the whole job alone.

In other words, Paul needs 21/2 = 10.5 hours to make the whole job alone.    ANSWER

At this point, the problem is solved completely and correctly.


-------------------------


What we observe in this case, is very typical situation.

The solution by @mananth was created by a computer code - which was a prototype of an Artificial Intelligence in its current state.

As soon as this code met a non-standard formulation, it produced wrong solution (= kind of gibberish).

Not only it produced wrong solution - it even did not check it, even did not notice it and even did not react
on wrong solution.

It shows, that the AI is in its infantile state and can work properly only if real persons and experts
accompany its work, checking every step.



Answer by n2(54) About Me  (Show Source):
You can put this solution on YOUR website!
.
Paul can do a certain job in half the time that Jim requires to do it.
Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours.
What length of time, in hours, would Paul, working alone, take to do the whole job?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


Let 'a' be the Jim's rate of work, i.e. part of work, which Jim makes in 1 hour.

Then the Paul's rate of work is 2a, according to the problem.


Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. 


It means that

    a + 10*(2a) = 1,    where '1' represents the whole job.


From this equation, we find

    a + 20a = 1  --->  21a = 1  --->  a = 1/21.


It means that Jim makes 1/21 of the Job per hour.
In other words, Jim needs 21 hours to make the whole job alone.

Hence, according to the problem, Paul needs half of 21 hours to make the whole job alone.

In other words, Paul needs 21/2 = 10.5 hours to make the whole job alone.    ANSWER



Answer by josgarithmetic(39736) About Me  (Show Source):
You can put this solution on YOUR website!
https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1106092.html

Answer by KMST(5337) About Me  (Show Source):
You can put this solution on YOUR website!
Jim worked alone for 1 hour and stopped.
Paul comes in, sees the work Jim did in 1 hour and says
"It would have taken me 1%2F2 to do that. I do any job in half the time it takes Paul to do it"
After Paul worked another 10 hours, the job was finished.
Then Jim said "SEE!, I could have done the whole thing in 10%2B1%2F2=highlight%2810.5%29 hours. I may only have a fourth-grade education, but I can work twice as fast as Paul, without knowing what algebra is about."

The problem with mananth solution seems to be that after getting to
((x-1)/x)/(2/x)=10 or %28%28x-1%29%2Fx%29%2F%282%2Fx%29=10 mananth apparently thought
"I could simplify the left side expression by writing it as %28%28x-1%29%2Fx%29%28x%2F2%29 because dividing by 2%2Fx is multiplying times x%2F2 to end with %28x-1%29%2Fx on the left and a simple expression on the right.
or I could simplify the equation by multiplying both sides by 2%2Fx"
Then mananth had one of those brain-farts and multiplied the left hand side times 2%2Fx and the right hand side times x%2F2 ending with %28x-1%29%2Fx on the left and 10%28x%2F2%29=5x on the right.
Keeping the equal sign in between, mananth concluded that Jim could have done the whole job in 2 hours, forgetting that it took Jim 10 hours to do part of the job.
We we all have one of those brain farts now and then. One professor told about answering a problem on a radio station show by saying that the top of an 8 foot ladder leaning again the side of a house would be 10 feet above the ground.