SOLUTION: Two employees together can prepare a large order in 2 hours. Working alone one employee takes three hours longer than the other.how long does it take each person working alone?

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Question 1028012: Two employees together can prepare a large order in 2 hours. Working alone one employee takes three hours longer than the other.how long does it take each person working alone?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Call the number of hours the faster worker can do the job in, x. Then the slower worker takes x+3 hours. The setup looks like this
2%2Fx+%2B+2%2F%28x%2B3%29+=+1
where the 1 corresponds to ONE large order, or one job in general.
Now solve by multiplying everything by x(x+3)...we get
2(x+3) + 2x = x(x+3)
2x + 6 + 2x = x^2 + 3x
4x + 6 = x^2 + 3x
0 = x^2 - x - 6
Factoring we get
(x - 3)(x + 2) = 0
and
x = 3 hours
x+3 = 6 hours