|
This Lesson (Had there were more workers, the job would be completed sooner) was created by by ikleyn(52750)  : View Source, ShowAbout ikleyn:
Had there were more workers, the job would be completed sooner
Problem 1A certain number of workers can do a work in 50 days.
Had there were 20 workers more it would be completed in 5 days less. How many workers are there?
Solution
Let "n" be the number of workers in the first case.
Then the number of workers in the hypothetical case is (n+20).
All the job is n*50 man-days in the first case, and (n+20)*45 man-days in the second case.
So the equation is
50n = 45(n+20).
Simplify and solve:
50n = 45n + 900,
5n = 900,
n = = 180.
It is your answer: 180 workers are there in the base case.
Problem 2Five workers have been hired to complete a job. If one additional worker is hired,
they could complete the job 10 days earlier. If the job needs to be completed 30 days earlier,
how many additional workers should be hired?
Solution
Let "a" be the rate of work of one worker per day.
Then the number of days for 5 workers to complete the job is ;
the number of days for 6 workers to complete the job is .
Thus, we can write this time equation
- = 10 days. (1)
It implies
- = 10,
= 10,
a = . (2)
+--------------------------------------------------------------+
| So, we found that under given condition the rate of work |
| is 1/300 of the job per day for each worker. |
+--------------------------------------------------------------+
Now we want to find the number n of additional workers (to 5 workers) to complete
the job 32 days earlier. For it, we write similar time equation to (1)
- = 30.
Substitute here a = 1/300, based on (2). You will get
- = 30.
To solve, simplify step by step. You will get
60 - = 30,
60 - 30 = ,
30 =
5 + n =
5 + n = 10.
n = 10 - 5 = 5.
+----------------------------------------------------------------+
| Second part of the solution can be worded in different way. |
+----------------------------------------------------------------+
We just found that the rate of work of one worker is 1/300 of the job per day.
It means that the entire job is 300 man-days.
5 workers can complete this job in 300/5 = 60 days.
We want the job be complete in 60-30 = 30 days.
Hence, 300/30 = 10 workers are needed, i.e. 10 - 5 = 5 workers should be added.
ANSWER. 5 workers should be hired in addition to the original 5 workers to complete the job 32 days earlier.
My other lessons on rate-of-work problems in this site are
- Rate of work problems
- Using Fractions to solve word problems on joint work
- Solving more complicated word problems on joint work
- Using quadratic equations to solve word problems on joint work
- Solving rate of work problem by reducing to a system of linear equations
- Solving joint work problems by reasoning
- Selected joint-work word problems from the archive
- Joint-work problems for 3 participants
- HOW TO algebreze and solve these joint work problems ?
- One unusual joint work problem
- Special joint work problems that admit and require an alternative solution method
- Snow removal problem
- Entertainment problems on joint work
- Joint work word problems for the day of April, 1
- OVERVIEW of lessons on rate-of-work problems
Use this file/link ALGEBRA-I - YOUR ONLINE TEXTBOOK to navigate over all topics and lessons of the online textbook ALGEBRA-I.
This lesson has been accessed 2357 times.
|
| |