Tutors Answer Your Questions about Radicals (FREE)
Question 992017: I am trying to solve an equation in which a radical is = to a variable expression but I am having problems. I would like to ask for your help.
After I square off both sides, I get 
On the left of the equal sign, the squares cancel out and if I multiply (x-2)(x-2) my problem now looks like this:
4x+13=x^2-4x+4
To continue solving, do I collect all terms to the right or to the left? This is my confusion, I hope you can help me.
Click here to see answer by josgarithmetic(39617)  |
Question 992036: I am not having good luck with this answer. Please help!!!
I squared off the expression 2x-3 and used the FOIL method to get this:
4x-12x+9=30-7x I continue by subtracting 4x-12x to get -8x+9=30-7x. Here's where I think I lose it.
Somewhere I'm missing something because I keep getting x=21 but the answer key says {3}
Click here to see answer by jim_thompson5910(35256) |
Question 992036: I am not having good luck with this answer. Please help!!!
I squared off the expression 2x-3 and used the FOIL method to get this:
4x-12x+9=30-7x I continue by subtracting 4x-12x to get -8x+9=30-7x. Here's where I think I lose it.
Somewhere I'm missing something because I keep getting x=21 but the answer key says {3}
Click here to see answer by macston(5194)  |
Question 992036: I am not having good luck with this answer. Please help!!!
I squared off the expression 2x-3 and used the FOIL method to get this:
4x-12x+9=30-7x I continue by subtracting 4x-12x to get -8x+9=30-7x. Here's where I think I lose it.
Somewhere I'm missing something because I keep getting x=21 but the answer key says {3}
Click here to see answer by MathTherapy(10552)  |
Question 992872: Can I get your help? My problem is this:
I started by subtracting the 1 from both sides which gave me  Now, would I add 4x^2 and x which would give me  Now my equation looks like this:  From here I would square both sides 
I get 9x^2+3x-1-3x+1-1=5x^3+7. If I continue, 3x-1-3x+1 would cancel out which makes the equation look like this:
9x^2-1=5x^3+7. I subtract 9x^2 from both sides and I subtract 7 from both sides so I end up with -8=-4x. Then I divide by -4 and my answer would be 2. Can you verify to see if I made a mistake?
Click here to see answer by Alan3354(69443)  |
Question 992872: Can I get your help? My problem is this:
I started by subtracting the 1 from both sides which gave me Now, would I add 4x^2 and x which would give me Now my equation looks like this: From here I would square both sides
I get 9x^2+3x-1-3x+1-1=5x^3+7. If I continue, 3x-1-3x+1 would cancel out which makes the equation look like this:
9x^2-1=5x^3+7. I subtract 9x^2 from both sides and I subtract 7 from both sides so I end up with -8=-4x. Then I divide by -4 and my answer would be 2. Can you verify to see if I made a mistake?
Click here to see answer by stanbon(75887) |
Question 993595: Hello!
Hope anyone can help me answer this :)
1.) A—b / a sqrt(b) –b sqrt(a)
2.) ab / a sqrt(b) — b sqrt(a)
The topic is rationalizing denominators using conjugates
Hope anyone can explain it too
Thank you! :)
Click here to see answer by Alan3354(69443) |
Question 993752: I'm really having a tough time with this problem, can you help me?
here is the problem:
 - +
I rewrote it using prime factorization and got this:
 - +
I simplified to this:
 - +
I tried to solve this and got + but the answer key shows the answer as:  - Can you tell me how they got that?
Click here to see answer by Alan3354(69443) |
Question 993752: I'm really having a tough time with this problem, can you help me?
here is the problem:
-+
I rewrote it using prime factorization and got this:
-+
I simplified to this:
-+
I tried to solve this and got + but the answer key shows the answer as: - Can you tell me how they got that?
Click here to see answer by MathTherapy(10552) |
Question 993742: Hello. I am having an issue solving this problem and I look to you for help. My problem is:
-+. By using prime factorization, I know that 12 = 2^2*3
50 = 5^2*2
72 = 3^2*2^3
Now, I plug these terms back in and I get:
-+ If I continue, I get:
-+
The answer key shows that the answer should be
- Can you see where I went wrong? I'm not coming up with the right answer.
Click here to see answer by Theo(13342)  |
Question 996998: Hello. I know it might sound a bit crazy but can you help me solve this radical equation? I have been so focused on other formulas that I forgot this one. My question is:
 I should start by adding x to both sides so the equationb now looks like this:  at this time, I square both sides to look like this:  Since the squares eliminate themselves on the left, I foil the right so the equation looks like this:
x+15=x^2+6x+9. Here is where I stop because the answer key has an answer of 1 but I'm not getting that no matter which way I go. Can you advise me?
Click here to see answer by Alan3354(69443) |
Question 996998: Hello. I know it might sound a bit crazy but can you help me solve this radical equation? I have been so focused on other formulas that I forgot this one. My question is:
I should start by adding x to both sides so the equationb now looks like this: at this time, I square both sides to look like this: Since the squares eliminate themselves on the left, I foil the right so the equation looks like this:
x+15=x^2+6x+9. Here is where I stop because the answer key has an answer of 1 but I'm not getting that no matter which way I go. Can you advise me?
Click here to see answer by ikleyn(52781)  |
Question 996998: Hello. I know it might sound a bit crazy but can you help me solve this radical equation? I have been so focused on other formulas that I forgot this one. My question is:
I should start by adding x to both sides so the equationb now looks like this: at this time, I square both sides to look like this: Since the squares eliminate themselves on the left, I foil the right so the equation looks like this:
x+15=x^2+6x+9. Here is where I stop because the answer key has an answer of 1 but I'm not getting that no matter which way I go. Can you advise me?
Click here to see answer by ankor@dixie-net.com(22740)  |
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