Tutors Answer Your Questions about Radicals (FREE)
Question 885778: Rationalize the denominator is my weakness when there are variables as I get confused with knowing how to simplify and what is the better method. These are some questions I have that I am stuck on:
sqrt(18x^2y)/sqrt(2y^3) (I think there might be factoring involved but I don't know how to factor in this type of problem)
forth root(2x)/forth root(3x^2) (I don't even know how to begin to solve this as it looks like it is in simplest form)
sqrt(63xy^3)/sqrt(7y) (I know that you have to multiple by sqrt(7y) but I'm not sure if the numerator will be sqrt(63xy^3*7y) or sqrt(441xy^4))
Also I am not too familiar with some of the rules involved with these types of problems and I have tried to research them but there is just to much variables and not enough explanations. If there could be explanations on the rules/methods used that would be great.
Click here to see answer by ankor@dixie-net.com(22740)   |
Question 886970: simplify radical form
√3(64x^5^7)
i perceive it should look like
√3(64x^5y^7)
simplified 64 = 8*8
√5 = 2.2
√7 = 2.6
(64^1/3)(x^5)((y^7)^1/3
but it's not working out.. i am supposed to assume all variables represent positive numbers..
Click here to see answer by Alan3354(69443)  |
Question 887296: {cuberoot(128x^5)}
I took the cube root and factored the 128 to get 2*64x^5
a 4 is pulled out and 2 is left in the cubed root.
Im not sure what to do about the x^5 in the cubed root.
I think you pull out x^5 and get a finished product of:
(4x^5){cube root(2)}
Would this be correct? Thanks for the help!
Click here to see answer by lwsshak3(11628) |
Question 887296: {cuberoot(128x^5)}
I took the cube root and factored the 128 to get 2*64x^5
a 4 is pulled out and 2 is left in the cubed root.
Im not sure what to do about the x^5 in the cubed root.
I think you pull out x^5 and get a finished product of:
(4x^5){cube root(2)}
Would this be correct? Thanks for the help!
Click here to see answer by MathTherapy(10551)  |
Question 887357: Multiply and Simplify:
{cube root(9x^7y^2z)} * {cube root(12xy^5y^2)}
I think you would factor to get {cube root(9*12x^8y^7z^3)}
you would then pull out a 3x^2y^2z and have 3x^2y^2{cube root(4x^2y)}
would 3x^2y^2z{cube root(4x^2y)} be the final answer? Thanks!
Click here to see answer by lwsshak3(11628) |
Question 887357: Multiply and Simplify:
{cube root(9x^7y^2z)} * {cube root(12xy^5y^2)}
I think you would factor to get {cube root(9*12x^8y^7z^3)}
you would then pull out a 3x^2y^2z and have 3x^2y^2{cube root(4x^2y)}
would 3x^2y^2z{cube root(4x^2y)} be the final answer? Thanks!
Click here to see answer by MathTherapy(10551) |
Question 887358: Rationalize each denominator and simplify:
{cube root(5/xy^2)}
you would rewrite it so it would be:
{cube root(5)}/{cube root(xy^2)}
Then you would multiply the numerator and denominator by {cube root(xy^2}
this would give you {cube root(5xy^2)}/xy^2
is this correct? Thanks!!!
Click here to see answer by Alan3354(69443) |
Question 887358: Rationalize each denominator and simplify:
{cube root(5/xy^2)}
you would rewrite it so it would be:
{cube root(5)}/{cube root(xy^2)}
Then you would multiply the numerator and denominator by {cube root(xy^2}
this would give you {cube root(5xy^2)}/xy^2
is this correct? Thanks!!!
Click here to see answer by lwsshak3(11628) |
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