Tutors Answer Your Questions about Radicals (FREE)
Question 58562: Hello again!
It says to simplify:
(\/(radical sign)it stretches completly across the whole thing)
\/98x^4y^3
I got this:
\/7*14*x^4*y^3=
\/14x^4*\/7y^3
How would I complete this? Did I do anything wrong so far?
Thank you
CH
Click here to see answer by funmath(2933) |
Question 58901: I have 2 questions. One I need to see if I got right and the other I have no clue about. Thanks to anyone willing to assist.
Solve the following equation for x.
23x^2 + 17x= -11
23x^2 + 17x + 11=0
I get that there is no solution b/c this can't be factored. Correct?
The other is 1 + radical(x-5) =0
I dont have the radical symbol. Just to be clear, x-5 is under the radical.
Click here to see answer by stanbon(75887) |
Question 58901: I have 2 questions. One I need to see if I got right and the other I have no clue about. Thanks to anyone willing to assist.
Solve the following equation for x.
23x^2 + 17x= -11
23x^2 + 17x + 11=0
I get that there is no solution b/c this can't be factored. Correct?
The other is 1 + radical(x-5) =0
I dont have the radical symbol. Just to be clear, x-5 is under the radical.
Click here to see answer by uma(370) |
Question 59525: (I have used the tiny ` characters to space and preserve formatting)
```````_``````````````_
x^2 \/3 + 6x + 7 \/3
TRIED:
------
``````'`````_
(x^2+7)\/3 =-6x
3x^2+21 = -18x
3x^2+18x+21 ->> Solved by quadratic formula
Didn't work :(
I have the feeling that I need to SQUARE both sides instead of multiplying by 3, but I don't see why multiplying by 3 wouldn't work, because it does the same thing to both sides.
Any help appreciated!
Click here to see answer by stanbon(75887) |
Question 59881: Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since.
2x^2=48
1) 2x^2/2=48/2
2) x^2=24
3) x=+-sq root 24
4) ????
Click here to see answer by funmath(2933) |
Question 59942: 10. Simplify Last question. I forgotten the next step for the question.
2(rs)12 +4(rs)27 then it's
2 (rs)6 (rs)2 + 4(rs)9 (rs) 3
What is my next step. Do I find the perfect squares of 4 and 9 or just the nine. I'm confusing myself again.
Click here to see answer by chitra(359) |
Question 60039: Hello. I really don't understand the whole simplifying radicals thing I learned today in class. I was wondering is you could explain it to me because my classmates couldn't help me.
The directions say to express each radical in simplest form.
under the radical sign it says 75x12(to the twelfth)y5(to the fifth).
one of the other ones says
4 as the index, then under the radical sign 48x3(to the third)y20(to the twentith)
if anyone could help me it would me greatly appreciated.Thanks.
Click here to see answer by stanbon(75887) |
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