Tutors Answer Your Questions about Radicals (FREE)
Question 713229: multiply
(square root of 11 minus 3)(square root of 11 minus 3)
I FOIL and get square root of 11 times square root of 11 minus 3 square root of 11 minus 3 square root of 11 plus 9.
then i simplify and get 11 minus 6 square root of 11 plus 9
then i subtract 11 to both sides and get
-6 square root of 11 minus 2
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 715617: what is the numerical value of 4 raise to onethird?
what is the numerical value of 32 raise to negative three halves?
what is the numerical value of (18/81) raise to three fourths?
what is the numerical value of (-32) raise to negative two fifth?
Click here to see answer by jsmallt9(3758) |
Question 717978: 2(radical sign))54
and -2(radical sign) 6a^3 multiply (radical sign)3a
When you have a number infront of the radical what do you do? and say you simplify a radical and then the answer has a number infront of the radical do you keep it or do you have to simplify it more like these problems?
Click here to see answer by Alan3354(69443)  |
Question 717978: 2(radical sign))54
and -2(radical sign) 6a^3 multiply (radical sign)3a
When you have a number infront of the radical what do you do? and say you simplify a radical and then the answer has a number infront of the radical do you keep it or do you have to simplify it more like these problems?
Click here to see answer by MathLover1(20849)  |
Question 719384: The solution of
sqrt(x+4)= x-2 ==> x=0 and x=5
x=5 is true since by substituting in the original equation yield 3=3
However,for x=0 we have sqrt(4)=-2 which give an incorrect solution... If we ignore the negative value of squrt(4).
My question is.. Why the negative value is ignored?
Click here to see answer by jsmallt9(3758) |
Question 720317: Here is my problem.
[SQRT(x + 7)] - 2[SQRT(x)] =-2
OR
√(x + 7) - 2√(x) = -2
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Now, the steps I took to solve this problem are to first square both sides:
[√(x + 7) - 2√(x)] * [√(x + 7) - 2√(x)] = 4
so then I FOIL the left side, resulting in:
(x+7) - [√(x + 7) * - 2√(x)] - [ - 2√(x) * √(x + 7)] + 4x
So then I thought to subtract (x+7) and (4x) to both sides
- [√(x + 7) * - 2√(x)] - [ - 2√(x) * √(x + 7)] = 4 - 4x - x - 7 (I think I'm supposed to switch the sign, because I've subtracted it and moved it to the opposite side, right?)
I think I'm correct up to this point, but now I have to square both sides again.
I think this left hand side could be re-written as:
-2[√(x + 7) * - 2√(x)]
Is this right? I'm subtracting it from itself, a negative, which could simply multiplied by -2. Anyway, now I need to square this again, so I assume the -2 becomes a 4 and I FOIL them separately?
FOILING the left side will get:
[√(x + 7) * - 2√(x)] * [√(x + 7) * - 2√(x)]
Which, when FOILed, looks like
(x+7) - [√(x+7) * -2√(x)] - [ - 2√(x) * √(x + 7)] + 4x
It looks exactly the same as before!! I'm just really confused by this problem, and I have a couple more like it, so I want to know if figuring this one out could help me solve the other ones.
I'm confused about FOILing the different sides, whether or not I can combine two square roots, and quite frankly, a lot of other things.
One of the options on the test is 9, and I think this is the answer, because I've inserted it into the original equation and it works, but I'm just confused about how to actually get 9 out of this..
Sorry for the long question. I hope it's not hard to understand. I'm just hoping someone can walk me through all the steps of solving a problem like this so I can do it easily in the future.
Click here to see answer by lwsshak3(11628) |
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