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Question 408751: The weight of an object on Earth varies according to the elevation of the object. In particular, the weight of an object follows this equation w=Cr^-2, where C is constant and r is the distance that the object is from the center of the earth.
Solve the equation w=Cr^-2 for r.
I am not sure where to start with this equation and no numbers to input the next problem states that sea level is 3,963 miles from center of the earth but I don't think I need to use that to solve for r in the first question. Please help!
Click here to see answer by richard1234(7193)  |
Question 412716: Factoring:
1. A farmer has 300 ft of fencing and wants to enclose a rectangular area of 5000 ft2. What dimensions should she use? (Hint: 5000 = 30 * 100)
A=5000 W=? L=? H=?
A= W*L*H
I know that we're supposed to put all of the numbers to one side and equal them to zero. Ex: 2(x+1)=0 ==> x=-1
Click here to see answer by checkley79(3341) |
Question 414097: Answer the following questions. Use Equation Editor to write mathematical expressions and equations.
Hint for this assignment: Pay attention to the units of measure. You may have to convert from feet to miles in this assignment. You can use 1 mile = 5,280 feet for your conversions.
1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: , where C is a constant, and r is the distance that the object is from the center of the earth.
a. Solve the equation for r. Solve the equation for C. Solve the equation for w.
b. Suppose that an object is 420 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is approximately 4,000 miles from the center of the earth.)
c. Use the value of C you found in the previous question to determine how much the object would weigh
i. 1,200 feet below sea level
ii. The top of Mt McKinley (20,500 feet above sea level)
2. The equation gives the distance, D, in kilometers that a person can see to the horizon from a height, h, in meters.
a. Solve this equation for h.
b. Mount Evans in the Rocky Mountain National Park, is 4,385 meters in elevation. How far can you see to the horizon from the top of Mount Evans? Can you see Cheyenne, Wyoming (about 260 kilometers away)? Explain your answer.
Click here to see answer by jsmallt9(3758) |
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