Tutors Answer Your Questions about Radicals (FREE)
Question 29888: Multiply and simplify. Assume that all variables in a radicand represent positive real numbers. The 3 here is the cube root.
3√50x10γ * 3√25x16γ to the 7th power
Can you tell me how to get started.
Thanks so much!!!
Click here to see answer by Cintchr(481)  |
Question 30005: Rationalize the denominators and simplify are the instructions from my instructor
3w over square root of y
i came up with 3w as a solution is this correct and could u show me how u came to get a solution
Click here to see answer by Cintchr(481) |
Question 30019: O.K My instructions were " for each function, find the specified function value, if it exists." The problem is
f(t)= square root of 5t-10; f(6), f(2), f(1), f(-1)
I can't figure out how to get the answers and what is "Does Not Exist"?
PLease help and thanks
Click here to see answer by sdmmadam@yahoo.com(530) |
Question 30069: Multiply and Simplify.
3(radical sign)50x^10y * 3(radical sign)25x^16y^7
The three's here are the cube root not multiplied. I hope this is understandable. I can't figure out how to get the radical sign in this text box. Thanks for all your help.
Click here to see answer by Cintchr(481) |
Question 30186: hi,
i need help on simplifying radical expressions with sqaure roots. They're are three different types of problems on my homework and i dont know how to solve them. I'm wondering if they are solved the same way and how to solve them...some examples on my homework are....  ....  ....and  ...it will be very appreciated if you help me...thanks
-kelsey larue
Click here to see answer by Cintchr(481) |
Question 30306: I am asked to simply this problem:
6^3a+2 multiplied by 6^2-2a over 6^a+5
(6 to the 3a+2 power multiplied by 6 to the 2nd power minus 2a power over 6 to the A power plus 5th power
6^3a+2 multiplied by 6^2-2a
---------------------------
6^a+5
Thank you
Click here to see answer by sdmmadam@yahoo.com(530) |
Question 30441: Ok, it just looks like all the help I've seen is too advanced to help me with this... here's the problem... (a^3 b^-6)^1/2.. I know this has to be simple, but I've been wracking my brain trying to figure it out.
Thanks!
Charity
Click here to see answer by Cintchr(481) |
Question 30507: When I try to graph or solve for (x)^(1/3) or other odd roots, I get a complex number when x is negative. I know that (-2)^3 = -8, so why isn't (-8)^1/3 =-2? I am trying to learn how to do the basics on a TI-89 T.
Thanks, Bruce
Click here to see answer by Earlsdon(6294) |
Question 30856: Whats the answer to this problem the square root of 108 and it has to be in its symplified form well it would be good if u gave me both answers the radical expression and it simplified
Click here to see answer by acerX(62) |
Question 30980: I don't understand how to do this problem:
(root)3x(squared) - 2x - 2(root)3 =0
I keep getting x=2root3 as my answer, but it's wrong. My teacher gave me the answer root3(+-)root21 / 3
How do I get that answer?
Click here to see answer by ikdeep(226)  |
Question 31146: I am having problem with the fractions.
4(1/4)s(1/3) T(-1/2)
____________________
[4s(2)t(-3)](-1/4)
All the numbers in parenthesis are exponents and the numbers in the brackets are together and -1/4 is its exponent the line represents a fraction
Click here to see answer by josmiceli(19441)  |
Question 29943: hi,
I was wondering if you could help figure how to work a couple of radical equations. I tried them tons of different ways but I don't think I have the right answers. I also have problems with 4th and 5th roots
1) square root of 1/2 plus 3square root of 3/8. I got square 2 over/divided by 2 plus 3square root 6 over/divided by 2.
2) 5th root of 1/8. I got 5th root of 4 over/divided by 2.
Click here to see answer by stanbon(75887) |
Question 31715: Please help me simplify this problem: square root of 8 divided by 2 times the square root of 5 plus the square root of six.
Sorry, I do not know how to make a square root sign so I could not type the problem out but I will type it out without the square root signs to give you some idea. The square root signs go over the 8, 5, and the six:
Ignore the ! (exclamation mark)
The six is supposed to be part of the denominator!
Thanks ahead of time for helping me!
Click here to see answer by Cintchr(481) |
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