Tutors Answer Your Questions about Radicals (FREE)
Question 1206442: I'm working on half-angle identities for trigonometry and I keep getting the wrong answer, or possibly in a different form than the book's answer.
I'll just ask about the answer which is basically rationalizing a root problem (with a fractional root within it).
I keep getting stuck on an intermediary step, as follows, from the solution in the book:
sqrt(1+sqrt(5))/sqrt2
which gives the solution:
sqrt(50-10sqrt(5))/10
I know I'm messing up with rationalizing the denominator and I can't figure it out.
I ran the plain text radicals above in Wolfram Alpha and it comes out basically as the problem/solution in the book.
Any help would be greatly appreciated.
Click here to see answer by greenestamps(13200)  |
Question 1069865: Sarah is collecting recyclables for a science project. On the first day she collects 35 recyclable objects. On the second day she has a total of 52 recyclables. On the third day she has a total of 69 recyclables. Determine if the scenario describes an arithmetic or a geometric sequence. Then, write the recursive formula for the sequence described.
Click here to see answer by mananth(16946)  |
Question 1069865: Sarah is collecting recyclables for a science project. On the first day she collects 35 recyclable objects. On the second day she has a total of 52 recyclables. On the third day she has a total of 69 recyclables. Determine if the scenario describes an arithmetic or a geometric sequence. Then, write the recursive formula for the sequence described.
Click here to see answer by Edwin McCravy(20055)  |
Question 1207668: The distance to the surface of the water in a well can sometimes be found by dropping an object into the well and measuring the time elapsed until a sound is heard. If x is the time (measured in seconds) that it takes for the object to strike the water, than x will obey the equation s = 16x^2, where s is the distance (measured in feet). It follows that x = sqrt{s}/4.
Suppose that y is the time it takes for the sound of the impact to reach your ears. Because sound waves are known to travel at a speed of about 1100 feet per second, the time y to travel the distance s will be y = s/1100. Now x + y is the total time that elapses from the moment that the object is dropped to the moment that a sound is heard.
We have the equation TOTAL TIME ELAPSED = (sqrt{s}/4) + (s/1100).
Find the distance to the water's surface if the total time elapsed from dropping a rock to hearing it hit water is 4 seconds.
Wow! That's a mouth full.
I rearranged the original equation to be
s + 275(sqrt{s}) = 4400
Stick here....
Click here to see answer by ikleyn(52781)  |
Question 1207669: A civil engineer relates the thickness T, in inches, and height H, in feet, of a square wooden pillar to its crushing load L, in tons, using the model
T = [(LH^2)/25)]^(1/4).
If a square wooden pillar is 4 inches thick and 10 feet high l, what us the crushing load?
Here is my set up:
4 = [(L(10)^2)/25)]^(1/4).
Is this correct?
Thanks.
Click here to see answer by ikleyn(52781)  |
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