SOLUTION: I have a question here and I don't know where to start. Can you help me? {{{sqrt(x-1)+2=sqrt(2x+5)}}}

Algebra ->  Radicals -> SOLUTION: I have a question here and I don't know where to start. Can you help me? {{{sqrt(x-1)+2=sqrt(2x+5)}}}       Log On


   

Question 997004: I have a question here and I don't know where to start. Can you help me?
sqrt%28x-1%29%2B2=sqrt%282x%2B5%29
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I have a question here and I don't know where to start. Can you help me?
sqrt%28x-1%29%2B2=sqrt%282x%2B5%29
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That's not a question, it's an equation.
If you want to solve for x:
sqrt%28x-1%29%2B2=sqrt%282x%2B5%29
Square both sides.
x-1+%2B+4sqrt%28x-1%29+%2B+4+=+2x%2B5
4sqrt%28x-1%29+=+x%2B2
Square again
16%28x-1%29+=+x%5E2+%2B+4x+%2B+4
x%5E2+-+12x+%2B+20+=+0
(x-2)*(x-10) = 0
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Check for extraneous values.