SOLUTION: Solve for w. {{{sqrt(-4w+44) = w-3}}} What I got before I got confused... {{{-sqrt(4w)}}} + {{{sqrt(44)}}} {{{-2sqrt(w)}}}+{{{2sqrt(11)}}} = {{{w-3}}} I ended up wit

Algebra ->  Radicals -> SOLUTION: Solve for w. {{{sqrt(-4w+44) = w-3}}} What I got before I got confused... {{{-sqrt(4w)}}} + {{{sqrt(44)}}} {{{-2sqrt(w)}}}+{{{2sqrt(11)}}} = {{{w-3}}} I ended up wit      Log On


   

Question 985517: Solve for w.
sqrt%28-4w%2B44%29+=+w-3
What I got before I got confused...
-sqrt%284w%29 + sqrt%2844%29
-2sqrt%28w%29+2sqrt%2811%29 = w-3
I ended up with something strange at the end of me simplifying this. :\

Found 2 solutions by rothauserc, Timnewman:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
square root(-4w + 44) = w - 3
square both sides of the =
-4w + 44 = w^2 -6w + 9
add 4w to both sides of =
44 = w^2 -2w + 9
subtract 44 from both sides of =
w^2 -2w -35 = 0
factor the polynomial
(w - 7) * (w + 5) = 0
two solutions, w = 7 or w -5
************************************************
check the answers
w = 7
square root( (-4*7) + 44) = 7 -3
square root( 16 ) = 4
4 = 4
***************************************
w = -5
square root( (-4*-5) + 44 ) = -5-3
square root( 64 ) = -8
-8 = -8
note square root is + or -
our answers check

Answer by Timnewman(323) About Me  (Show Source):
You can put this solution on YOUR website!
Hi dear,
take the square of bothside so as to get gid of the square root.
Hence,
(-4w+44)=(w-3)^2
-4w+44=w^2-6w+9
w²-2w-35=0
solve the quadratic equation:
(w-7)(w+5)=0
From the above,
w=7 or w=-5
HOPE THIS HELPS: