SOLUTION: In the right triangle, triangle ABC, the altitude line segment CD is at a right angle to the hypotenuse. You can use {{{ CD=sqrt(( AD )( DB )) }}} to find certain lengths. a) fi

Algebra ->  Radicals -> SOLUTION: In the right triangle, triangle ABC, the altitude line segment CD is at a right angle to the hypotenuse. You can use {{{ CD=sqrt(( AD )( DB )) }}} to find certain lengths. a) fi      Log On


   

Question 982054: In the right triangle, triangle ABC, the altitude line segment CD is at a right angle to the hypotenuse. You can use +CD=sqrt%28%28+AD+%29%28+DB+%29%29+ to find certain lengths.
a) find AD if CD=10 and DB=4
+CD=sqrt%28%28+AD+%29%28+DB+%29%29+
+10=sqrt%28%28+AD+%29%28+4+%29%29+
+10=sqrt%28+4AD+%29+
+10%5E2=%28sqrt%28+4AD+%29%29%5E2+
+100=4AD+
+100%2F4=%28+4AD+%29%2F4+
+25+=+AD+
b) find DB if AD=20 and CD=15
+CD=sqrt%28%28+AD+%29%28+DB+%29%29+
+15=sqrt%28%28+20+%29%28+DB+%29%29+
+15=sqrt%28+20DB+%29+
+15%5E2=%28sqrt%28+20DB+%29%29%5E2+
+225=20DB+
+225%2F20=%28+20DB+%29%2F20+
+45%2F4+=+DB+ or 11.25
are my answers correct?

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
One way to check them is with graph paper, pencil and ruler, and count the
squares.  In the first one below, by counting the little squares on the
graph paper, you see that AD=25,CD=10,DB=4. And if you put the corner of
a sheet of paper at C, you will see that it is a right angle of 90°.



It appears that you have done good work, and neatly too, using the
notation of this site.

Edwin