SOLUTION: 7/ cubed root of the square root of 9x^2. Rationalize the denominator

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Question 947798: 7/ cubed root of the square root of 9x^2.
Rationalize the denominator
Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
7/ cubed root of the square root of 9x^2.
Rationalize the denominator
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7/cbft[sqrt(9x^2)]]
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= 7/(3x^2)^(1/3)
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= 7/(3x)^(2/3))
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Multiply numerator and dinominator by (3x)^(1/3) to get:
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= (7*(3x)^(1/3))/(3x)
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Cheers,
Stan H.
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Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
7%2Froot%283%2C%28sqrt%289x%5E2%29%29%29

Attempt to rationalize can be done in steps.


will take care of the cubed root part.

sqrt%289x%5E2%29%2Fsqrt%289x%5E2%29
will take care of the square root part.

Another method, if you want to just stay with the positive square rooting,
sqrt%289x%5E2%29
is the same as
3x

I have not solve the problem for you. Only I gave guidance and the factors to use.