SOLUTION: How to solve -16t^2+vt?

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Question 935019: How to solve -16t^2+vt?
Found 2 solutions by Fombitz, josmiceli:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Can't solve it, it's an expression.
You can simplify.
-16t%5E2%2Bvt=t%28v-16t%29
Repost another question if you need to.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can't solve it because it's not an equation
You need an = sign somewhere
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What you probably have is:
+h%28t%29+=+-16t%5E2+%2B+vt+
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This plots the height, +h+ of an object
thrown upward with initial velocity +v+
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Are you being asked for the maximum height
or for the time, t+ for the object
to come back to ground?
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For it to come back to ground, just say:
+h%28t%29+=+o+ ( height = 0 )
+-16t%5E2+%2B+vt+=+0+
+t%2A%28+-16t+%2B+v+%29+=+0+
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There are 2 solutions:
+t+=+0+ ( the instant the object is thrown )
+t+=+v%2F16+ ( the instant the object lands }
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So your answer is +t+=+v%2F16+
( units are ft, ft/sec, ft/sec2