SOLUTION: √x+1+5=x solve with extraneous solution

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Question 894132: √x+1+5=x solve with extraneous solution
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x%2B1%29%2B5=x
sqrt%28x%2B1%29=x-5
x%2B1=x%5E2-10x%2B25
x%5E2-11x%2B24=0
%28x-3%29%28x-8%29=0
Two solutions:
x-3=0
x=3
Verifying,
sqrt%283%2B1%29%2B5=3
2%2B5=3
False, this is the extraneous solution.
.
.
.
x-8=0
x=8
Verifying,
sqrt%288%2B1%29%2B5=8
sqrt%289%29%2B5=8
3%2B5=8
8=8
True.