SOLUTION: I think this particular problem <radical x - 1 = x - 3> cannot be solved by I need verfify I'm doing it correctly. First I remove the radical from the equation by squaring both sid
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Question 88552This question is from textbook
: I think this particular problem cannot be solved by I need verfify I'm doing it correctly. First I remove the radical from the equation by squaring both sides = x - 1 = x^2 - 6x + 9. Next I need to make the equation equal to zero = 0 = x^2 - 7x + 10. Then I need to factor (x - 2)(x - 5). When I plug -2 back into check I end up with radical -3 = -5 and when I plug -5 I end up with radical -6 = -8. Therefore is it true this equation has no solution? This question is from textbook
You can put this solution on YOUR website! First I remove the radical from the equation by squaring both sides = x - 1 = x^2 - 6x + 9. Next I need to make the equation equal to zero = 0 = x^2 - 7x + 10. Then I need to factor (x - 2)(x - 5). When I plug -2 back into check I end up with radical -3 = -5 and when I plug -5 I end up with radical -6 = -8. Therefore is it true this equation has no solution?
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Then you factor to get:
(x-2)(x-5)=0
Since the product is zero one of these factors must be zero:
If x-2=0, x=2
If x-5=0, x=5
The solutions you need to test are x=2 or x=5
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Cheers,
Stan H.
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