SOLUTION: SOLVE... 1. ROOT OF 4X+12-4=0 SIMPLIFY.... 1. ROOT OF 50 OVER ROOT OF 2 SIMPLIFY... 1. 6ROOT OF 6X+ 3 ROOT OF 6X EVALUATE IF POSSIBLE... 1.-3 ROOT OF 64

Algebra ->  Radicals -> SOLUTION: SOLVE... 1. ROOT OF 4X+12-4=0 SIMPLIFY.... 1. ROOT OF 50 OVER ROOT OF 2 SIMPLIFY... 1. 6ROOT OF 6X+ 3 ROOT OF 6X EVALUATE IF POSSIBLE... 1.-3 ROOT OF 64      Log On


   

Question 86697: SOLVE...
1. ROOT OF 4X+12-4=0
SIMPLIFY....
1. ROOT OF 50 OVER ROOT OF 2
SIMPLIFY...
1. 6ROOT OF 6X+ 3 ROOT OF 6X
EVALUATE IF POSSIBLE...
1.-3 ROOT OF 64
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
SOLVE...
1. ROOT OF 4X+12-4=0
:
sqrt%284x%2B12%29 - 4 = 0
sqrt%284x%2B12%29 = +4; add 4 to both sides
4x + 12 = 16; squared both sides, (gets rid of the radical)
4x = 16 - 12; subtract 12 from both sides
4x = 4
x = 1
Substitute 1 for x in the original equation and see that it checks out
:
:
SIMPLIFY....
1. ROOT OF 50 OVER ROOT OF 2
:
sqrt%2850%29%2Fsqrt%282%29
sqrt%2825%2A2%29%2Fsqrt%282%29; find the perfect square inside the radical
5%2Asqrt%282%29%2Fsqrt%282%29; extract the sqrt of 25
Ans = 5; The sqrt%282%29's cancel
:
:
SIMPLIFY...
1. 6ROOT OF 6X+ 3 ROOT OF 6X
:
6%2Asqrt%286x%29+%2B+3%2Asqrt%286x%29 = 9%2Asqrt%286x%29; sqrt(6x) are like terms, just add them
:
:
EVALUATE IF POSSIBLE...
1.-3 ROOT OF 64
:
-3%2Asqrt%2864%29: we know the sqrt(64) = 8
-3 * 8 = -24
:
:
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