SOLUTION: {{{p^2}}}+5p-5=0

Algebra ->  Radicals -> SOLUTION: {{{p^2}}}+5p-5=0      Log On


   



Question 86296: p%5E2+5p-5=0
Answer by scianci(186) About Me  (Show Source):
You can put this solution on YOUR website!
p%5E2+5p-5=0
You'll need to apply the quadratic formula:
x+=+%28-b+%2B-+sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29 =
%28-5+%2B-+sqrt%285%5E2-4%2A1%2A%28-5%29%29%29%2F%282%2A1%29 =
%28-5+%2B-+sqrt%285%5E2-4%2A1%2A%28-5%29%29%29%2F2 =
%28-5+%2B-+sqrt%2825-%28-20%29%29%29%2F2 =
%28-5+%2B-+sqrt%2845%29%29%2F2 =
%28-5+%2B-+3sqrt%285%29%29%2F2