SOLUTION: SqRt5 - SqRt2 / SqRt3 - SqRt2 {{{(sqrt(5) - sqrt(2))/(sqrt(3) - sqrt(2))}}} This is not in a textbook it was a question on a test and I am curious what the answer is and it is

Algebra ->  Radicals -> SOLUTION: SqRt5 - SqRt2 / SqRt3 - SqRt2 {{{(sqrt(5) - sqrt(2))/(sqrt(3) - sqrt(2))}}} This is not in a textbook it was a question on a test and I am curious what the answer is and it is       Log On


   

Question 85456: SqRt5 - SqRt2 / SqRt3 - SqRt2
%28sqrt%285%29+-+sqrt%282%29%29%2F%28sqrt%283%29+-+sqrt%282%29%29
This is not in a textbook it was a question on a test and I am curious what the answer is and it is worked out.
Answer by scianci(186) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply the top and bottom by he conjugate of %28sqrt%283%29+-+sqrt%282%29%29 , which is %28sqrt%283%29+%2B+sqrt%282%29%29:
%28sqrt%285%29+-+sqrt%282%29%29%2F%28sqrt%283%29+-+sqrt%282%29%29 * %28sqrt%283%29+%2B+sqrt%282%29%29%2F%28sqrt%283%29+%2B+sqrt%282%29%29 =
%28sqrt%285%29+-+sqrt%282%29%29%28sqrt%283%29+%2B+sqrt%282%29%29%2F%283+-+2%29 =
%28sqrt%2815%29+%2B+sqrt%2810%29+-+sqrt%286%29+-+2%29