SOLUTION: sqrt2x+4 = sqrt3x
(The "+4" is included under the first square root/radical sign)
Normally I would include what I've tried but I'm completely stumped on this one.
I remember b
Algebra ->
Radicals
-> SOLUTION: sqrt2x+4 = sqrt3x
(The "+4" is included under the first square root/radical sign)
Normally I would include what I've tried but I'm completely stumped on this one.
I remember b
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Question 851504: sqrt2x+4 = sqrt3x
(The "+4" is included under the first square root/radical sign)
Normally I would include what I've tried but I'm completely stumped on this one.
I remember being taught radical equations, in which, using what I was taught I was doing these steps:
Square each side
sqrt2x+4 = sqrt3x ---> (sqrt2x+4)^2 = (sqrt3x)^2
in which afterwards you would simplify
2x + 4 = 3x?
After that I didn't know what to do.
Thanks! Answer by Fombitz(32388) (Show Source):
