SOLUTION: The life expectancy of a woman is given by the model L(t)= √0.3t^3-5.5t^2 +70t+6000 where L is average life expectancy of a woman and t is the number of years after 1990. Fi
Algebra ->
Radicals
-> SOLUTION: The life expectancy of a woman is given by the model L(t)= √0.3t^3-5.5t^2 +70t+6000 where L is average life expectancy of a woman and t is the number of years after 1990. Fi
Log On
Question 831700: The life expectancy of a woman is given by the model L(t)= √0.3t^3-5.5t^2 +70t+6000 where L is average life expectancy of a woman and t is the number of years after 1990. Find the average life expectancy of a woman in the year 2015. Round your answer correct to two decimal places if needed.
Please help.
FYI: all the numbers from 0.3t are under a radical. Thanks Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! L(25)=sqrt(.3*25^3-5.5*25^2+70*25+6000)
=sqrt(.3*15625-5.5*625+1750+6000)
=sqrt(4687.5-3437.5+7750)
=sqrt(9000)
=94.87
.
Ed
