SOLUTION: please check this for me? I have to factor completely. 49x^2-25 -25+79x^2=0 -25+25+49x^2=0+25 0+49x^2=0+25 49x^2=0+25 49x^2=25

Algebra ->  Radicals -> SOLUTION: please check this for me? I have to factor completely. 49x^2-25 -25+79x^2=0 -25+25+49x^2=0+25 0+49x^2=0+25 49x^2=0+25 49x^2=25      Log On


   

Question 81247: please check this for me? I have to factor completely.
49x^2-25
-25+79x^2=0
-25+25+49x^2=0+25
0+49x^2=0+25
49x^2=0+25
49x^2=25
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I have to factor completely.
49x^2-25 = (7x-5)(7x+5)
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-25+79x^2=0
79x^2-25=0
(sqrt(79)x -5)(sqrt(79)x+5)=0
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-25+25+49x^2=0+25
Simplify to get 49x^2-25=0
(7x-5)(7x+5)=0
x=5/7 or x=-5/7
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0+49x^2=0+25
Simplify to get:
49x^2-25=0
same result
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49x^2=0+25
49x^2=25
same result
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Cheers,
Stan H.