SOLUTION: i have attempted to solve can someone please check for me? sqrt(2x+2)-6=0 2x+2^2=(6^2) 2x+2=36 2x=34 x=17

Algebra ->  Radicals -> SOLUTION: i have attempted to solve can someone please check for me? sqrt(2x+2)-6=0 2x+2^2=(6^2) 2x+2=36 2x=34 x=17      Log On


   

Question 81243: i have attempted to solve can someone please check for me?
sqrt(2x+2)-6=0
2x+2^2=(6^2)
2x+2=36
2x=34
x=17
Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%282x%2B2%29-6=0
Get the square root term alone on one side of the equation:
sqrt%282x%2B2%29=6
Square both sides:
2x%2B2=36
Solve for x:
2x=34
highlight%28x=17%29
Great job, you got it right!
Good Luck,
tutor_paul@yahoo.com