SOLUTION: can some one check this for me please? sqrt{{{y+2}}}=5 sqrt{{{y+2}}}=5 (sqrt{{{y+2}}})^2=52 y+2=25 y=23

Algebra ->  Radicals -> SOLUTION: can some one check this for me please? sqrt{{{y+2}}}=5 sqrt{{{y+2}}}=5 (sqrt{{{y+2}}})^2=52 y+2=25 y=23      Log On


   

Question 79038: can some one check this for me please?
sqrty%2B2=5
sqrty%2B2=5
(sqrty%2B2)^2=52
y+2=25
y=23
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You did this correctly. As always you can plug in y=23 into y to check the answer.
note: since we squared the square root we'll only be looking for the positive square root
Check:
sqrt%28y%2B2%29=5
sqrt%2823%2B2%29=5 Plug in y=23
sqrt%2825%29=5
5=5 works. So this verifies our answer