SOLUTION: Simplify {{{root(3,-16xy^6)}}} A. -2y^2{{{root(3,2x)}}} B. 2y^2{{{root(3,-x)}}} C. 2y^2{{{root(3,-2x)}}} D. -4y^2{{{root(3,x)}}} I thought it was C. {{{root(3,16xy^6)

Algebra ->  Radicals -> SOLUTION: Simplify {{{root(3,-16xy^6)}}} A. -2y^2{{{root(3,2x)}}} B. 2y^2{{{root(3,-x)}}} C. 2y^2{{{root(3,-2x)}}} D. -4y^2{{{root(3,x)}}} I thought it was C. {{{root(3,16xy^6)      Log On


   

Question 769516: Simplify root%283%2C-16xy%5E6%29
A. -2y^2root%283%2C2x%29
B. 2y^2root%283%2C-x%29
C. 2y^2root%283%2C-2x%29
D. -4y^2root%283%2Cx%29
I thought it was C. root%283%2C16xy%5E6%29 = root%283%2C-2x%2A8y%5E6%29=root%283%2C-2x%29root%283%2C8y%5E6%29=2y^2root%283%2C-2x%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify root%283%2C-16xy%5E6%29
A. -2y^2root%283%2C2x%29
B. 2y^2root%283%2C-x%29
C. 2y^2root%283%2C-2x%29
D. -4y^2root%283%2Cx%29
I thought it was C. root%283%2C16xy%5E6%29 = root%283%2C-2x%2A8y%5E6%29=root%283%2C-2x%29root%283%2C8y%5E6%29=2y^2root%283%2C-2x%29
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Since it's an odd root,
= -2y%5E2root%283%2C2x%29
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Both answers are correct, but there's less under the radical when the -1 is removed.