SOLUTION: I need help please. Simplify 5[sqrt2]/2-i by rationalizing the denominator. I multiplied it by 2+i/2+i, right? I ended up w/ the answer of 15i[sqrt2]/4-i, but that's not righ

Algebra ->  Radicals -> SOLUTION: I need help please. Simplify 5[sqrt2]/2-i by rationalizing the denominator. I multiplied it by 2+i/2+i, right? I ended up w/ the answer of 15i[sqrt2]/4-i, but that's not righ      Log On


   



Question 768376: I need help please. Simplify 5[sqrt2]/2-i by rationalizing the denominator.
I multiplied it by 2+i/2+i, right? I ended up w/ the answer of 15i[sqrt2]/4-i, but that's not right. I'm not sure what I'm doing wrong. Answer options:
A. [sqrt2](2-i)/3
B. 10/2[sqrt2]-i[sqrt2]
C. 5[sqrt2](2-i)/3
D. 2[sqrt2]+i[sqrt2]

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I need help please. Simplify 5[sqrt2]/2-i by rationalizing the denominator.
I multiplied it by 2+i/2+i, right? I ended up w/ the answer of 15i[sqrt2]/4-i
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it's (10*sqrt(2) + 5i*sqrt(2))/(4-i^2)
The DEN is 4 - i^2 = 5
= (10sqrt(2) + 5i*sqrt(2))/5
= 2sqrt%282%29+%2B+i%2Asqrt%282%29