You can put this solution on YOUR website! find tangent and normal line equation for f(x) at x=2.
F(x) = 3x^2 +2
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F'(x) = 6x
x = 2 --> the point (2,14)
m = 6x = 12
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tangent line is slope = 12 thru the point (2,14)
y = 12x - 10
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Normal is slope = -1/12 thru (2,14)
y = -x/12 + 85/6