SOLUTION: HELP A POOR GIRL OUT! 1. x/3SQRT(2x-3)-1/SQRT(2x-3)=1/3 2. CUBERT(2x3 - 24) = -x 3. (4x4 - 48)^(1/4) = x 4. SQRT(x2 - 8x) = -3

Algebra ->  Radicals -> SOLUTION: HELP A POOR GIRL OUT! 1. x/3SQRT(2x-3)-1/SQRT(2x-3)=1/3 2. CUBERT(2x3 - 24) = -x 3. (4x4 - 48)^(1/4) = x 4. SQRT(x2 - 8x) = -3       Log On


   

Question 767260: HELP A POOR GIRL OUT!
1. x/3SQRT(2x-3)-1/SQRT(2x-3)=1/3
2. CUBERT(2x3 - 24) = -x
3. (4x4 - 48)^(1/4) = x
4. SQRT(x2 - 8x) = -3
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!


1)

x%2F%283%2Asqrt%282%2Ax+-+3%29%29+-+1%2Fsqrt%282%2Ax+-+3%29+=+1%2F3

Multiplying both sides by 3%2Asqrt%282%2Ax+-+3%29 we get

x+-+3+=+sqrt%282%2Ax+-+3%29

Squaring both sides

x%5E2+-+6%2Ax+%2B+9+=+2%2Ax+-+3

or

x%5E2+-8%2Ax+%2B+12+=+0

Solving by factorization

%28x+-+6%29%2A%28x+-+2%29+=+0

x = 6 or x = 2



2)

%282%2Ax%5E3+-+24%29%5E%281%2F3%29+=+-x

Cubing both sides

2%2Ax%5E3+-+24+=+%28-x%29%5E3+=+-x%5E3

Grouping like terms

3%2Ax%5E3+=+24

x%5E3+=+8

x+=+2



3)

%284%2Ax%5E4+-+48%29%5E%281%2F4%29+=+x

Raising both sides to the power of 4

4%2Ax%5E4+-+48+=+x%5E4

Grouping like terms

3%2Ax%5E4+=+48

x%5E4+=+48%2F3+=+16

Taking the 4th root

x+=+2 or x+=+-2



4)

sqrt%28x%5E2+-+8%2Ax%29+=+-3

Squaring both sides

x%5E2+-+8%2Ax+=+9

x%5E2+-+8%2Ax+-+9+=+0

Solving by factorization

%28x+-+9%29%2A%28x+%2B+1%29+=+0

x = 9 or x = -1





Hope you got it:)